프로그래머스/level 1
[프로그래머스] 다트게임
binaryJournalist
2021. 9. 15. 00:04
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출처: https://programmers.co.kr/learn/challenges
** Javascript
function solution(dartResult) {
const bo = dartResult.split(/\d/g).filter((item) => item.length);
const s = dartResult.split(/[SDT]|\*|\#/g).filter((item) => item.length);
let strg = [];
for (let i = 0; i < 3; i++) {
const [ bonus, option ] = bo[i].split("");
let score = Number(s[i]) ** "_SDT".indexOf(bonus);
strg.push(score);
if (option === "*") {
for (let j = i - 1; j < i + 1; j++) {
strg[j] = strg[j] * 2;
}
}
if (option === "#") {
strg[i] = strg[i] * -1;
}
}
return strg.reduce((acc, curr) => acc += curr, 0);
}
** Python
import re
def solution(dartResult):
s = re.findall(r'\d+', dartResult)
bo = [i for i in re.split(r'(\d+)', dartResult) if not i.isdigit()][1:]
_sum = [0, 0, 0]
for i in range(len(s)):
_sum[i] = int(s[i])
for j in bo[i]:
if '_SDT'.find(j) > 0:
_sum[i] = _sum[i] ** '_SDT'.find(j)
elif j == "*":
_sum[i] = _sum[i] * 2
if i != 0:
_sum[i-1] = _sum[i-1] * 2
else:
_sum[i] = _sum[i] * -1
return sum(_sum)
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